Q: A star is "big", why do we need to care about quantum mechanics?
Sirius A, the Dog Star, and Sirius B
Image Credit & Copyright: NASA, H.E. Bond and E. Nelan
The limit on the precision to which position and velocity of a particle can be known (Heisenberg's uncertainty principle): 
Thus the available number of quantized states is
Let's start by considering a classical gas in non-extreme regime. Then
the particles are distributed according to a Maxwell-Boltzmann
distribution 
to violate QM!
From the previous lecture we have already seen the Maxwell-Boltzmann distribution (Pols 3.13)
Taking the ratio to our equation for 
Q: How can we use this to find when QM effects become important?
We can expect that for "very cold" stars or "very dense" stars the ideal gas EOS will not be appropriate.
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Image Credit: Hugo Spinelli
The occupation of quantum states of energy between 
where 
which can be 
The total number of particles with momentum between 
that is integrating the phase space distribution in momentum one
should find the spatial density 
Let's now consider a gas of electrons. These are the particles in the
ionized gas of the star that will first start feeling QM effects,
since 
These particles have spin 1/2, thus they are fermions, and obey 
A fully (completely) degenerate gas is one where all the particles are in the lowest possible energy state, corresponding to the limit 
Fermions (such as electrons) occupy a sphere in momentum space with radius 
and we used 
the normalization coming from the total number density of electrons
The Fermi momentum depends only on the density of electrons for a fully degenerate electron gas.
We can now calculate the pressure for the gas using our original equation for pressure (Pols 3.4):
We just neet just need the appropriate 
In this case 
gas) and 
where we used Pols Eqn. 3.18 for 
A fully degenerate, non-relativistic electron gas has a polytropic EOS with exponent 
In the extremely relativistic limit, we can assume 
one power of 
A fully degenerate extremely/ultra-relativistic gas, the EOS will again be a polytrope with exponent now 
In general, we should expect a smooth transition between these two
regimes as 
One can estimate the density at the transition with the
condition 
The density around which we expect a transition from non-relativistic to ultra-relativistic gas only depends on 
The equations derived above are valid in the strict limit of 
necessary for full degeneracy.
In reality it is sufficient to have 
Electrons are Fermions that need to obey Pauli's principle at very low 
they can exert a much larger pressure than predicted by the classical ideal gas.
The pressure is a polytrope, independent of temperature T! Exponent depending on if the gas is NR/ER.
This is the situation of a "white dwarf" (WD, such as Sirius B), which are the remnants for the vast majority of stars, including the Sun.
In some stars, the radiation field is so strong that is has a non-negligible contribution to the pressure.
We use this to determine the number density:
and the energy density due to radiation
where
which is closely related to the Stefan-Boltzmann constant 
Relying again on the ultra-relativistic nature of photons, we know
that 
Putting all things together:
If the electrons are not degenerate (they can be described classically as in Pols 3.19),
In practice, stellar evolution code often rely on tabulated EOS, which account for many non-ideal effects.

EOS are ultimately one of the points of contact between stellar physics and atomic physics and statistical mechanics:
The ρ–T coverage of the EOS used by the eos module. From the MESA V instrument paper by Paxton et al. 2019.
Note: these are profiles, not history data.
In class: Work on ICA here with partner, I will ask one or two people to share and describe plots at the end of class.
After Class: End of day today, September, 9, 2025
nbconvert to D2L, the progress you have made.ICAs are not always designged to be completed but rather worked on in class, submit what you have when you leave the class even if you did not make much progress.